Great job!  Very simplified!

❤ thanks

🙏🙏🙏👍

thank you i understand motors much better.

Thank you very much Sir, appreciate you 👌👍👍👍👍👍👍👍👍

Thank you for the video, I understand motor calcs much better. Taking the big journeymens test next week. Wish me luck!

You sir, are the best thank you for sharing your knowledge 🙂

Thank you very much for what you do , I just wanted to state that on motors overload we have to use next size down .

I’m going through this right now and the last question you changed it when you showed the answers it said temperature rise of 35 and you didn’t have that down when you put the answers

The FLC for single phase and three phase has an adjustment factor of 125%.  You forgot to multiply the FLC by 1.25

Can you do steps 3, 4 and 5?

Someone know how to calculate a 300hp motor and its cable size use?

I thought for overload protection you use the FLA, not the FLC. And you didn’t talk about downsizing the overload protection.

Does anyone have the answers to the questions he left at the end?

2023 code book
Am I lost or did 430.32 (2) change???

For step 1, you should use the table in the NEC as opposed to the nameplate. That is because the motor may be replaced with a less efficient motor.

@6:53 if it's continuous it's 1.25. Just incase it doesn't have Service factor or Temp

Shouldn’t the answer for the 4th question at 13:44 be 50 since the temperature is less than 40 degrees Celsius??

On the overload protection we should use the nameplate times the percentage, right? This video says to use full load current from the code book but if you look at 430.32 it says nameplate full load current. Thank you for the videos.

Thanks for your videos, do you have a more robust test prep program for the journeyman  (2020Montana) test, of what prep test program do you recommend.