What happened to the square of 9×^4(×^2+4)^2

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What  happened to the 2 square of the bracket of 9x^(x^2+4)^2

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Pls what happened to the square at (x* +4)*

That place if we first take the square we (x^4+16)9x^2=9x^6+144x^2

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Thank you sir for making the teaching easy, but why did you ignore the square on that (x^2+4)^2: the last question. Please recheck and tell me. Thank you

What happened to that squared in (x^2+4)

9x² × (x²+4)²
Why did you ignore the square which was attached to the bracket? When multiplying the 9x² to it.  I had x⁴+8x²+16 when I squared the bracket
The final answer was 21x⁶+120x⁴+144x²

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Sir please check the last part of the product rule