Only a genius can solve this algebra equation | Math olympiad mathematics
Math Master TV
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Only a genius can solve this algebra equation | Math olympiad mathematics
Learn how to solve a+b+c=17 , a^2 + b^2 + c^2 = 113 , √a + √b + √c = 7 using advanced [Algebra / Exponents / Geometry] techniques! Try solving it yourself first, then watch the step-by-step solution to check your answer.
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11 Comments
2^2+2^2+3^2=17
2^4+2^4+3^4=113
A solution is
sqrta=sqrtb=2. sqrtc=3
a=b=4. c=9. Other solutions are
a=c=4. b=9. and
b=c=4. a=9
a,b.c>or=0.
a,b.c<or=16
a,b,c<or=10 => 0<or=a,b,c<or=10
a^0.5+b^0.5+c^0.5=2+2+3=7
a+b+c=4+4+9=17
a^2+b^2+c^2=16+16+81=113
Only a genius can solve this algebra equation | Math olympiad mathematics
Math Master TV
67,602 views
Only a genius can solve this algebra equation | Math olympiad mathematics
Learn how to solve a+b+c=17 , a^2 + b^2 + c^2 = 113 , √a + √b + √c = 7 using advanced [Algebra / Exponents / Geometry] techniques! Try solving it yourself first, then watch the step-by-step solution to check your answer.
🎯 IDEAL FOR:
International Math Olympiad (IMO) Aspirants
High School & University Entrance Exam Prep
SAT Math, GRE, & Scholarship Aptitude Tests
Math Enthusiasts & Competitive Exam Students
📚 MASTER MATHEMATICS WITH OUR PLAYLISTS:
👉 Complete Math Olympiad Solutions:
Maths Olympiad
🔔 JOIN THE MATH MASTER TV COMMUNITY:
If you love challenging math problems, subscribe to Math Master TV for daily step-by-step Olympiad tutorials, shortcut techniques, and concept breakdowns!
👍 Like | Share | Subscribe to support free, high-quality math education.
#MathOlympiad #Algebra #MathMasterTV #SATMath #CompetitiveMath