Me as a 9th grader doing it easily

Bruh there aint no way that question on thumbnail is hard for harvard students 🫩

Let a=log\base2(x)
=>x=2^a
=>log\base3(x)=a.log\base3(2)
=>a+a.log\base3(2)=5
a=5/(1+log\base3(2))
=5/(log\base3(6))=5.log6(3)
=>x=2^(5log6(3))

lnx/ln2+lnx/ln3=5, lnx=5/(1/ln2+1/ln3)=5ln2 ln3/(ln6), x= e^[5ln2 ln3/(ln6)]=32^(ln3/ln6)

👍💯